Question

One soulution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water. How much of each should be mixed together in order to obtain 280 quarts of a soulution that is 3 parts salt to 7 parts water?

PLS HELP!!!!

Answer 1

120

Explanation:

Given,

Solution A contains 2 parts salt to 8 parts water

Solution B contains 3 parts salt to 5 parts water

Target Mixture contains3 parts salt to 7 parts water:

Expressing the salt concentration in decimal form

Solution A: 2/(2 + 8) = 2/10 = 0.20 salt

Solution B: 3/(3 + 5) = 3/8 = 0.375 salt

Mixed Solution: s/(3 + 7) = 3/10 = 0.30 salt

Since target mixture is 280 quarts

If the amount of 0.375 salt present in mixed solution = x

Then, the amount of 0.20 salt, y = 280 – x

Using a typical mixture equation

0.375x + 0.20(280-x) = 0.30(280)

0.375x + 56 - 0.20x = 84

Subtract 56 from both sides of the equation

0.375x - 0.20x + 56 – 56 = 84 – 56

0.375x - 0.20x = 28

0.175x = 28

Divide both sides of the equation by 0.175

0.175x/0.175 = 28/0.175

x = 160

y = 280 – x

y = 280 – 160

y = 120