Question

A 16.1 kg block is dragged over a rough, horizontal surface by a constant force of 96.7 N acting at an angle of 31.7° above the horizontal. The block is displaced 99.9 m, and the coefficient of kinetic friction is 0.216. Find the work done by the 96.7 N force. The acceleration of gravity is 9.8 m/s². Answer in units of J.

Answer 1

The work done by the force is found by multiplying the horizontal component of the applied force with the distance over which the force is applied.

Step-by-step explanation:

The work done by a force is calculated using the equation W = Fd cos(θ), where W is the work, F is the magnitude of the force applied, d is the distance over which the force is applied, and θ is the angle between the force and the direction of displacement. In this problem, we have a constant force of 96.7 N acting at an angle of 31.7 degrees above the horizontal while the block is displaced 99.9 m. To find the work done by this force, we use the horizontal component of the force, which is F cos(θ) = 96.7 N * cos(31.7 degrees). The calculation gives us the work done by the force.