Final answer:
(x, y) is not a solution to the system of equations 2x-5y=4 and -3x+2y=5
Step-by-step explanation:
To determine if (x, y) is a solution to the system of equations 2x-5y=4 and -3x+2y=5, we substitute the values of x and y into the equations and check if both equations are true.
Let's substitute x and y into the first equation:
2(x) - 5(y) = 4
2x - 5y = 4
Now substitute x and y into the second equation:
-3(x) + 2(y) = 5
-3x + 2y = 5
If both equations are true, then (x, y) is a solution to the system of equations. If not, then it is not a solution.
Let's do the calculations:
2x - 5y = 4 becomes 2(x) - 5(y) = 4 becomes 2x - 5y = 4
-3x + 2y = 5 becomes -3(x) + 2(y) = 5 becomes -3x + 2y = 5
If we substitute the given values of x and y into the equations and both equations are true, then (x, y) is a solution to the system of equations. If not, then it is not a solution.
Let's substitute the values of x and y into the equations:
2(3) - 5(-2) = 4
6 + 10 = 4
16 = 4
-3(3) + 2(-2) = 5
-9 - 4 = 5
-13 = 5
Since both equations are not true when substituting the values of x=3 and y=-2, (x, y) is not a solution to the system of equations.