Final answer:
The volume of 0.160 M HNO₃ needed to neutralize 70.0 mL of 0.170 M KOH is 70.0 mL.
Step-by-step explanation:
To determine the volume of HNO₃ needed to neutralize a given volume of KOH, we can use the relationship between the molarities of the two solutions and the stoichiometry of their reaction.
First, let's write the balanced equation for the neutralization reaction between HNO₃ and KOH:
HNO₃(aq) + KOH(aq) → H₂O(ℓ) + KNO₃(aq)
From the equation, we can see that the molar ratio between HNO₃ and KOH is 1:1. Therefore, the volume of 0.160 M HNO₃ needed to neutralize the 70.0 mL of 0.170 M KOH is also 70.0 mL.