Question

A machine having an input of 90,000 ft-lb per minute operates at an efficiency of 65

1) 58,500 ft-lb/min
2) 55,000 ft-lb/min
3) 61,500 ft-lb/min
4) 63,500 ft-lb/min

Answer 1

The machine with an input of 90,000 ft-lb per minute and working at 65% efficiency has an output of 58,500 ft-lb per minute.

Step-by-step explanation:

The question involves the concept of efficiency in physics, where efficiency is the ratio of output work to input work. To find the output of a machine operating at 65% efficiency with an input of 90,000 ft-lb per minute, we use the formula:

Efficiency (%) = (Output Work / Input Work) × 100

Output Work = (Efficiency × Input Work) / 100

Substituting the given values:

Output Work = (65 × 90,000) / 100

Output Work = 58,500 ft-lb/min

Therefore, the machine produces an output of 58,500 ft-lb per minute at 65% efficiency.