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Determine the ka for a weak acid if a 0.10 m solution of the acid has [H+] = 4.6 x 10⁻⁴?

User Unikorn
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Final answer:

To determine the acid dissociation constant (Ka) for a weak acid with a given solution concentration and hydronium ion concentration, use the expression Ka = [H+]^2 / [HA]. The calculated Ka for the acid in question with [H+] = 4.6 x 10^-4 M and [HA] = 0.10 M is 2.116 x 10^-6.

Step-by-step explanation:

To determine the Ka for a weak acid when given the concentration of the acid solution and the concentration of hydronium ions ([H+]), we can use the expression Ka = [H+]2 / [HA], where Ka is the acid dissociation constant, [H+] is the concentration of hydronium ions, and [HA] is the initial concentration of the acid before dissociation.

Given that the concentration of the acid solution ([HA]) is 0.10 M and the [H+] is 4.6 x 10-4 M, we can plug these values into the formula:

Ka = (4.6 x 10-4)2 / 0.10

Upon calculating, we will get:

Ka = (2.116 x 10-7) / 0.10 = 2.116 x 10-6

User Rahul Shakya
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