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4 times a number minus twice another number is -16 the sum of the two numbers is -1 find the numbers

User Dympna
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1 Answer

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Final answer:

To solve this problem, assume that the first number is x and the second number is y. Set up the equations 4x - 2y = -16 and x + y = -1. Solve the system of equations using the elimination method to find the values of x and y. The two numbers are -3 and 2.

Step-by-step explanation:

To solve this problem, let's use algebra. Let's assume that the first number is x and the second number is y. According to the problem, 4 times a number minus twice another number is -16, so we can set up the equation 4x - 2y = -16.

We are also given that the sum of the two numbers is -1, so we can set up the equation x + y = -1.

To solve this system of equations, we can use either the substitution or elimination method. Let's use the elimination method. Multiply the second equation by 2 to make the coefficients of y the same in both equations.

The equations become:

4x - 2y = -16

2x + 2y = -2

Add the two equations together, eliminating y:

6x = -18

Divide both sides by 6 to solve for x:

x = -3

Substitute this value of x back into one of the original equations to solve for y. Let's use the second equation:

-3 + y = -1

Add 3 to both sides:

y = 2

Therefore, the two numbers are -3 and 2.

User Hyuan
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