Question

Butane, C₄H₁₀ reacts with excess oxygen to produce carbon dioxide gas and water. What volume of CO₂ is produced when 1.5 moles of butane react completely?

Answer 1

To calculate the volume of CO2 produced when 1.5 moles of butane react completely, we can use the stoichiometry of the reaction and the molar volume of CO2. The balanced equation shows that 1 mole of butane produces 8 moles of CO2, so 1.5 moles of butane will produce 12 moles of CO2. Since the volume of a gas is directly proportional to the number of moles at constant temperature and pressure, the volume of CO2 produced will be 12 times the molar volume of CO2 at the given temperature and pressure.

Step-by-step explanation:

The balanced equation for the reaction between butane (C4H10) and oxygen (O2) to produce carbon dioxide (CO2) and water (H2O) is:

C4H10 + 13O2 → 8CO2 + 10H2O

To calculate the volume of CO2 produced when 1.5 moles of butane react completely, we need to use the stoichiometry of the reaction. From the balanced equation, we can see that 1 mole of butane produces 8 moles of CO2. Therefore, 1.5 moles of butane will produce 1.5 * 8 = 12 moles of CO2.

Since the volume of a gas is directly proportional to the number of moles at constant temperature and pressure, the volume of CO2 produced will be 12 times the volume of 1 mole of CO2. Therefore, the volume of CO2 produced when 1.5 moles of butane react completely is 12 times the molar volume of CO2 at the given temperature and pressure.