Final answer:
The potential difference between the ends of a 2000m wire moving perpendicularly to a 3x10⁻µ T magnetic field at a velocity of 1000m/s is 6 volts.
Step-by-step explanation:
To compute the potential difference between the ends of a 2000m wire moving perpendicularly to a magnetic field of magnitude 3x10⁻µ T, we can use the formula for motional electromotive force (emf), which is given by № = Bvl, where № is the induced emf, B is the magnetic field strength, v is the velocity of the wire, and l is the length of the wire.
Plugging in the given values: B = 3x10⁻µ T, v = 1000m/s, and l = 2000m, we get:
№ = (3x10⁻µ T) × (1000m/s) × (2000m) = 6V.
The potential difference between the ends of the wire is therefore № = 6 volts.