Final answer:
To calculate the freezing point of a 14.75m aqueous solution of ethylene glycol, you need to determine the molality of the solution and use the freezing point depression equation. The molality can be found by dividing the moles of solute by the mass of solvent in kilograms. The freezing point depression can then be calculated using the freezing point constant and the molality.
Step-by-step explanation:
The freezing point of a solution depends on the concentration of the solute. In this case, the solute is ethylene glycol and the solvent is water. To calculate the freezing point depression, we first need to determine the molality of the ethylene glycol solution. We can use the formula:
molality = moles of solute / kilograms of solvent
Since the solution is 14.75m, it means that there are 14.75moles of ethylene glycol per 1000g of water. However, we only have the mass of the solution, so we need to convert the mass of water to kilograms:
1kg = 1000g
Since we have 500g of water, the mass in kilograms is 0.5kg.
Now we can calculate the molality:
molality = 14.75moles / 0.5kg = 29.5m
The freezing point depression can be calculated using the equation:
ΔTf = Kf * molality
Where ΔTf is the freezing point depression and Kf is the freezing point constant.
Since the freezing point constant is not provided in the question, you will need to refer to the list of colligative constants to find the appropriate value for ethylene glycol.