19.4k views
1 vote
C is the incenter of isosceles triangle abd with vertex angle ∠abd. Does the following proof correctly justify that triangles abc and dbc are congruent?

1) Yes, because the incenter of a triangle is equidistant from the three sides of the triangle.
2) No, because the incenter of a triangle is not necessarily equidistant from the three sides of the triangle.
3) Cannot be determined based on the given information.

User Fundhor
by
8.2k points

1 Answer

5 votes

Final answer:

The proof does not correctly justify that triangles ABC and DBC are congruent because the incenter of a triangle is not necessarily equidistant from the three sides of the triangle. Hence the correct answer is option 2

Step-by-step explanation:

The proof does not correctly justify that triangles ABC and DBC are congruent. The statement in option 1 is incorrect. The incenter of a triangle is not necessarily equidistant from the three sides of the triangle. Option 2 correctly states that the incenter of a triangle is not necessarily equidistant from the three sides.

Therefore, the answer is 2) No, because the incenter of a triangle is not necessarily equidistant from the three sides of the triangle.

User Agua From Mars
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.