Question

Calculate Δrh for the following reaction: c(s) H₂O(g)→co(g) H₂(g) use the following reactions and given Δrh 's. c(s) O₂(g)→CO₂⁺(g) , Δrh= -393.5 kjmol-1 2co(g) O₂(g)→2CO₂⁺(g) , Δrh= -566.0 kjmol-1 2H₂(g) O₂(g)→2H₂O(g) , Δrh= -483.6 kjmol-1

Answer 1

The ΔHr for the given reaction is -566 kJ. We can calculate ΔHr for the given reaction using Hess's law and the given ΔHr's:

Step-by-step explanation:

We can calculate ΔHr for the given reaction using Hess's law and the given ΔHr's:

Step 1: Reverse Equation (1) (change the sign of ΔH):

• 2 CO(g) → 2 C(s) + O₂(g) ΔH = +221.0 kJ

Step 2: Use Equation (2) as written:

• C(s) + O₂(g) → CO₂(g) ΔH = -393.5 kJ

Step 3: Multiply Equation (2) by 2:

• 2 C(s) + 2 O₂(g) → 2 CO₂(g) ΔH = -787.0 kJ

Step 4: Add Equations (1) and (3) together:

• 2 CO(g) + 2 C(s) + 2 O₂(g) → 2 C(s) + 2 O₂(g) + 2 CO₂(g) ΔH = -566 kJ

So, ΔHr for the given reaction c(s) + H₂O(g) → CO(g) + H₂(g) is -566 kJ.