66.3k views
1 vote
Find the slope of the line tangent to the curve 3x² y cosy=(√3 π)/2 at the point (-1,π6) ?

User Eemmrrkk
by
7.4k points

1 Answer

4 votes

Final answer:

The slope of the tangent line to the curve can be found by differentiating the given equation with respect to x, and then solving for dy/dx. The value of dy/dx at the point (-1, π/6) gives the slope of the tangent.

Step-by-step explanation:

To find the slope of the tangent line to the curve at a given point, we need to take the derivative of the curve with respect to x and evaluate it at the point of interest. The given curve is 3x² y cosy=(√3 π)/2, and we need to find the tangent at the point (-1,π/6). We can use implicit differentiation to find dy/dx as the slope of the tangent line.

First, differentiate both sides of the equation with respect to x:

  • Derive 3x² y with respect to x using the product rule.
  • Derive cosy with respect to x considering y as a function of x.
  • On the right side, since we have a constant, its derivative will be 0.

After differentiating, isolate dy/dx and evaluate it at the given point.

If the differentiation is done correctly, you would find that at the point (-1, π/6), the slope of the tangent line (dy/dx) can then be calculated by substituting the x and y values into this derivative.

User SantiClaus
by
7.0k points