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Given Vx = 19 m/s and Vy = 44 m/s, find the magnitude of the vector.

User Hamchapman
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Final answer:

The magnitude of the vector, given its components Vx = 19 m/s and Vy = 44 m/s, is calculated using the Pythagorean theorem and is approximately 47.93 m/s.

Step-by-step explanation:

The student is asking how to find the magnitude of the vector given its horizontal component, Vx = 19 m/s, and its vertical component, Vy = 44 m/s. The magnitude of a vector can be calculated using the Pythagorean theorem for the resultant of two perpendicular vectors.

To calculate the magnitude (v), we use the formula:

v = √(Vx² + Vy²)

Substituting the given values:

v = √((19 m/s)² + (44 m/s)²)

Calculating further:

v = √(361 + 1936)

v = √2297

v ≈ 47.93 m/s

Thus, the magnitude of the vector is approximately 47.93 m/s.

User Jaege
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