Question

Information

Problem 12.00E8 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS
Imagine another universe, where alternate electrons and protons have electric charge with magnitude 3.2 x 10-19 C but
opposite signs. In that universe, an alternate electron and an alternate proton are situated in an "alternate hydrogen
atom", separated by a distance of 5.29 x 10-11 m. Coulomb's law is valid in that universe, and Coulombs constant is the
same as in our universe, 9 x 109 N-m2/c².
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Problem 12.00E8.a - Calculating the electrostatic force
Calculate the magnitude of the electrostatic force exerted on the alternate electron by the alternate proton.
The magnitude of the electrostatic force is
x 10-8 N.

Answer 1

Using Coulomb's Law, the magnitude of the electrostatic force between the alternate proton and electron in the other universe is found to be 9.678 x 10^-8 N.

Step-by-step explanation:

To calculate the magnitude of the electrostatic force exerted on the alternate electron by the alternate proton in an alternate universe, we can use Coulomb's Law, which is given by the formula:

F = k * |q1 * q2| / r^2

where:

• k is Coulomb's constant (9 x 10^9 N-m^2/C^2),
• q1 and q2 are the magnitudes of the charges (3.2 x 10^-19 C), and
• r is the separation distance (5.29 x 10^-11 m).

By plugging these values into the formula, we'll get:

F = (9 x 10^9) * (3.2 x 10^-19 C)^2 / (5.29 x 10^-11 m)^2

After calculations, the magnitude of the electrostatic force is:

F = 9.678 x 10^-8 N

This result corresponds to the force that the alternate proton exerts on the alternate electron, which, due to Newton's third law, is the same force that the electron exerts on the proton.