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Solve the system of quadratic and linear equations: y=x²-3x-5, y=x+3

User Gospodin
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Final answer:

To solve the given system consisting of a quadratic equation (y = x² - 3x - 5) and a linear equation (y = x + 3), we set them equal to each other, rearrange the terms, and solve for x using the quadratic formula, obtaining x = 2 ± √3. We then use these x values to find corresponding y values.

Step-by-step explanation:

To solve the system of quadratic and linear equations:

  • Quadratic Equation: y = x² - 3x - 5
  • Linear Equation: y = x + 3

We set these equations equal to each other because they both equal y:

x + 3 = x² - 3x - 5

Rearrange the equation to find x:

0 = x² - 3x - 5 - (x + 3)

0 = x² - 4x - 8

Solve for x using the quadratic formula:

x = ± √(b² - 4ac) / (2a), where a = 1, b = -4, c = -8

Plugging in these values, we get two solutions for x:

x = (4 ± √(16 + 32)) / 2

x = (4 ± √48) / 2

x = (4 ± 4√3) / 2

Which simplifies to:

x = 2 ± √3

Substitute these x values back into either the quadratic or linear equation to find corresponding y values.

User Ardavan Kalhori
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