Question

Solve the following equation algebraically: 2x² = 50. a. plus-or-minus 0.2 b. plus-or-minus 7.07 c. plus-or-minus 5 d. plus-or-minus 12.5

1) plus-or-minus 0.2
2) plus-or-minus 7.07
3) plus-or-minus 5
4) plus-or-minus 12.5

Answer 1

To solve the equation 2x² = 50, first divide both sides by 2, resulting in x² = 25. Then take the square root of both sides, giving x = ±5. Hence, the correct answer is option c: plus-or-minus 5.

Step-by-step explanation:

The goal is to solve the quadratic equation algebraically, given by 2x² = 50. To find the value of x, we first divide both sides of the equation by 2 to isolate the x² term:

x² = ½ × 50

x² = 25

To solve for x, we take the square root of both sides of the equation. Since the square root has both a positive and a negative solution, we get:

x = ±√25

x = ± 5

Therefore, the solution is option c: plus-or-minus 5.