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5 votes
B
A
C
A. 35°
D
F
If m2CDB 50°, what is mBDG?
G
H

B A C A. 35° D F If m2CDB 50°, what is mBDG? G H-example-1
User Avoliva
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1 Answer

4 votes

The angle EDG in the square is 40°, as determined by properties of bisected angles, perpendicular diagonals, and the sum of triangle angles.

To find the angle EDG, we need to use some properties of a square and its diagonals. Here are the steps:

First, we know that the diagonal EG bisects the angle DEG, so we can write ∠DEG = 2∠EDG.

Second, we know that the diagonal BD is perpendicular to the diagonal EG, so we can write ∠BDE = 90°.

Third, we know that the angle CDB is given as 50°, so we can write ∠CDB = 50°.

Fourth, we can use the fact that the sum of the angles in a triangle is 180° to write ∠BDE + ∠CDB + ∠EDB = 180°.

Fifth, we can substitute the values of ∠BDE and ∠CDB from the previous steps and solve for ∠EDB. We get ∠EDB = 180° - 90° - 50° = 40°.

Sixth, we can use the fact that the opposite angles of a square are equal to write ∠EDG = ∠EDB = 40°.

Therefore, the answer is ∠EDG = 40°.

The question probable may be:

If m∠CDB = 50°, what is m∠EDG?

User Pratheesh
by
7.8k points