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Suppose you are driving your 1500kg care along a straight road at a constant speed of 30 m/s. If you suddenly lift your foot from the gas pedal, the car decelerates with a = 0.05(g). What is the deceleration of the car?

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Final answer:

The deceleration of a 1500kg car that coasts to a stop when the driver lifts their foot off the gas pedal at a deceleration rate of 0.05(g) is 0.49 m/s².

Step-by-step explanation:

When driving a car with a mass of 1500kg at a constant speed of 30 m/s and you lift your foot from the gas pedal, the car experiences a deceleration. Given that deceleration is expressed as a = 0.05(g), with g representing the acceleration due to gravity (approximately 9.8 m/s²), we can calculate the deceleration of the car. To find the deceleration of the car, you can simply multiply the given factor by the acceleration due to gravity: deceleration = 0.05 * 9.8 m/s² = 0.49 m/s². Therefore, the deceleration of the car when lifting your foot off the gas pedal is 0.49 m/s².

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