Question

Please help quick thanks

Answer 1

Explanation:

(
`x_(1)` ,
`y_(1)` )

(
`x_(2)` ,
`y_(2)` )

d =
`\sqrt{(x_(2) -x_(1) )^2+(y_(2) -y_(1) )^2}`

~~~~~~~~~~~~~~~

A ( 3 , 6 )

B ( 0 , 1 )

C ( 4 , 0 )

AB =
`√((0-3)^2 + (1-6)^2)` = 3√5 ≈ 6.71

AC =
`√((4-3)^2 + (0-6)^2 )` = √37 ≈ 6.08

BC =
`√((4-0)^2 + (0-1)^2 )` = √17 ≈ 4.12

AB ≠ AC ≠ BC ⇒ Δ ABC is a scalene triangle