Final answer:
To calculate the moles of F₂ required to produce 38.5 grams of PF₃, we need to use the balanced equation and convert grams of PF₃ to moles. We need 0.544 moles of F₂ to produce 38.5 grams of PF₃.
Step-by-step explanation:
To calculate the moles of F₂ required to produce 38.5 grams of PF₃, we need to use the balanced equation provided. The equation is:
Sn (s) + 2HF (g) → SnF₂ (s) + H₂ (g)
From the equation, we can see that 2 moles of HF react with 1 mole of SnF₂. We need to find the number of moles of HF required to produce 38.5 grams of PF₃. To do this, we need to convert grams of PF₃ to moles using the molar mass (141.387 g/mol). Then, we use the mole ratio from the balanced equation to find the moles of HF.
Given:
- Mass of PF₃ = 38.5 g
- Molar mass of PF₃ = 141.387 g/mol
Step 1: Convert grams of PF₃ to moles:
Moles of PF₃ = Mass of PF₃ / Molar mass of PF₃
Moles of PF₃ = 38.5 g / 141.387 g/mol
Moles of PF₃ = 0.272 mol
Step 2: Use the mole ratio from the balanced equation to find the moles of HF:
Moles of HF = Moles of PF₃ * (2 moles of HF / 1 mole of SnF₂)
Moles of HF = 0.272 mol * (2 mol HF / 1 mol SnF₂)
Moles of HF = 0.544 mol
Therefore, we would need 0.544 moles of F₂ to produce 38.5 grams of PF₃.