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Rachel just hopped on the edge of a merry-go-round. What are her linear and angular speeds if the diameter of the merry-go-round is 14 feet and it takes 7 seconds for it to make a complete revolution? Round the solutions to two decimal places.

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Final answer:

Rachel's linear speed on the merry-go-round is approximately 6.28 feet per second and her angular speed is approximately 0.45 radians per second, after conversion from revolutions per second.

Step-by-step explanation:

To calculate Rachel's linear and angular speeds on the merry-go-round, we must first find the circumference using the provided diameter. The diameter is 14 feet, so the circumference (C) is C = πd, which is approximately 43.98 feet (π times 14 feet). Given that it takes 7 seconds for the merry-go-round to make a complete revolution, the linear speed (v) can be calculated as the circumference divided by the revolution time, so v = C / T, which equals about 6.28 feet per second, rounded to two decimal places.

The angular speed (ω) is the number of revolutions per second which is 1/7 rev/s, and this can be converted to radians per second by multiplying by . So, ω = (1/7) / (2π), which equals approximately 0.45 radians per second, also rounded to two decimal places.

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