Final answer:
The bonds ranked from least polar to most polar based on the electronegativity differences are C-I (least polar), C-N (moderately polar), and C-O (most polar).
Step-by-step explanation:
To rank the bonds from least polar to most polar, we must consider the electronegativity differences between the atoms. Polar bonds arise from differences in electronegativity between two atoms involved in a bond. A larger difference in electronegativity indicates a more polar bond.
- Carbon-Iodine (C-I) bond: Iodine has a lower electronegativity than chlorine or oxygen. Therefore, the difference in electronegativity between carbon and iodine is relatively small, making the C-I bond the least polar among those listed.
- Carbon-Nitrogen (C-N) bond: Nitrogen has a higher electronegativity than carbon, but lower than that of oxygen. This results in a moderate difference in electronegativity, indicating that the C-N bond is more polar than the C-I bond, but less polar than the C-O bond.
- Carbon-Oxygen (C-O) bond: Oxygen is more electronegative than both nitrogen and iodine. The electronegativity difference between carbon and oxygen is the greatest among the three pairs, so the C-O bond is the most polar.
Thus, the bonds ranked from least polar to most polar are: C-I, C-N, and C-O.