Final answer:
The concentration of the NaCl solution after dilution to 192.0mL is 0.5 M, calculated using the dilution equation M1V1 = M2V2.
Step-by-step explanation:
The concentration of a solution formed by diluting 30.0mL of a 3.2 M NaCl solution to 192.0mL can be calculated using the dilution equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the final solution.
To find the final concentration (M2), you rearrange the equation to M2 = (M1V1) / V2. Substituting the known values gives M2 = (3.2M * 30.0mL) / 192.0mL. After performing the calculations, M2 = 0.5M.
Therefore, the concentration of the NaCl solution after dilution is 0.5 M.