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What is the probability that the last 4 digits of a 9 digit social security number are all odd?

User Irukandji
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3 Answers

3 votes

Final answer:

The probability that the last four digits of a 9-digit social security number are all odd is 1/16, which is equivalent to 0.0625.

Step-by-step explanation:

The question is about calculating the probability that the last four digits of a social security number are all odd. Each digit has a 1 in 2 chance of being odd (1, 3, 5, 7, or 9), since there are five odd numbers out of ten possible numbers (0-9). Since each digit is selected independently, we find the probability by multiplying the individual probabilities for each of the four digits.

The calculation is as follows: (1/2) × (1/2) × (1/2) × (1/2) = 1/16. So, the probability that the last four digits of a social security number are all odd is 1/16 or 0.0625.

User Zann Anderson
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7.5k points
2 votes

Final answer:

The probability that the last four digits of a 9-digit social security number are all odd is 1/16, which is equivalent to 0.0625.

Step-by-step explanation:

The question is about calculating the probability that the last four digits of a social security number are all odd. Each digit has a 1 in 2 chance of being odd (1, 3, 5, 7, or 9), since there are five odd numbers out of ten possible numbers (0-9). Since each digit is selected independently, we find the probability by multiplying the individual probabilities for each of the four digits.

The calculation is as follows: (1/2) × (1/2) × (1/2) × (1/2) = 1/16. So, the probability that the last four digits of a social security number are all odd is 1/16 or 0.0625.

User Egil
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3 votes

Answer:

The probability that each of the last four digits of a social security number is prime is 16/625.

Step-by-step explanation:

There are 10 possible digits for each of the last four digits of a social security number (0-9). there are 4 favorable outcomes (2,3,5,7).

- Number of favorable outcomes / Total number of possible outcomes

-The probability of selecting a prime digit = 4 / 10

-Simplifying the fraction now= Probability of selecting a prime digit = 2 / 5

-To find the probability that each of the last four digits is prime, we multiply the probabilities together:

Probability = (2/5) * (2/5) * (2/5) * (2/5)

we now have= Probability = 16 / 625

-If this is incorrect please forgive me! <33

User Nurettin
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