Question

A seismic shot point and a seismic geophone are 10m apart on surface. The upper layer is a till with a P-wave velocity of 2000m/s. The layer below is a basalt with a velocity of 6km/s. The p-wave travel time to the interface 9m below and back is:

Answer 1

The P-wave travel time to an interface 9m below the surface and back to a seismic geophone, with a P-wave velocity of 2000m/s in the material, is 9 milliseconds.

Step-by-step explanation:

The question is asking how to calculate the P-wave travel time to an interface 9 meters below the surface and back to a seismic geophone, given the P-wave velocity of the material (till) through which it is traveling. The provided P-wave velocity is 2000 meters per second (m/s).

To find the total travel time for the P-waves, we use the formula:

Travel Time = (2 * Distance) / Velocity

Since the distance to the interface and back to the surface is twice the depth (2 * 9 m = 18 m), we can calculate the travel time as follows:

Travel Time = (2 * 9 m) / 2000 m/s = 18 m / 2000 m/s = 0.009 seconds or 9 milliseconds.