Question

Calculate the number of moles of ZnCl₂, in 180.0 mL of 0.330 M solution.

A) 5.94 x 10² mol
B) 1.83 mol
C) 0.545 mol
D) 59.4 mol

Answer 1

The number of moles of ZnCl₂ in a 180.0 mL of 0.330 M solution is 0.0594 mol, which is equivalent to 59.4 mmol.

Step-by-step explanation:

To calculate the number of moles of ZnCl₂ in a 180.0 mL of 0.330 M solution, you need to use the concentration of the solution (Molarity, M) and the volume of the solution in liters. The formula to find the number of moles is:

Moles = molarity (M) × volume (L)

First, convert the volume from milliliters to liters:

180.0 mL = 0.180 L

Now, multiply the molarity by the volume in liters:

0.330 M × 0.180 L = 0.0594 mol

Therefore, the correct answer is B) 0.0594 mol, which corresponds to 59.4 mmol since 1 mol is equivalent to 1000 mmol.