Final Answer:
Therefore, the amount of 4.0 M NaOH solution required to make 2.0 liters of a 0.02 M solution is 10 mL (option B).
Step-by-step explanation:
To solve this, we can use the formula for dilution:
C1V1 = C2V2
Where:
C1 = concentration of the initial solution
V1 = volume of the initial solution
C2 = concentration of the final solution
V2 = volume of the final solution
C1 = 4.0 M (concentration of the 4.0 M NaOH solution)
C2 = 0.02 M (concentration of the final solution)
V2 = 2.0 liters (volume of the final solution)
Let's calculate V1:
C1V1 = C2V2
V1 = (C2 * V2) / C1
V1 = (0.02 M * 2.0 L) / 4.0 M
V1 = (0.04 mol) / 4.0 mol/L
V1 = 0.01 L = 10 mL
Therefore, the amount of 4.0 M NaOH solution required to make 2.0 liters of a 0.02 M solution is 10 mL (option B).