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A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the balloon contain at 1.35 atm and 253 K?

A) 22.2 L
B) 87.5 L
C) 11.4 L
D) 45.0 L
E) 58.6 L

1 Answer

2 votes

Final answer:

To find the volume of the gas in the balloon at different conditions, we can use the ideal gas law. By rearranging the equation and plugging in the given values, we can find the initial volume and the final volume of the balloon. The volume of the gas at 1.35 atm and 253 K is 100 L.

Step-by-step explanation:

To solve this problem, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Step 1: Convert the given values to the appropriate units. The initial pressure is 2575 mm Hg, which is equal to 3.400 atm. The initial temperature is 353 K, and the final temperature is 253 K.

Step 2: Use the ideal gas law to find the initial volume. Rearrange the equation to solve for V: V = (nRT) / P. Plug in the values: V = (1 mol * 3.400 atm * 353 K) / 3.400 atm = 353 L.

Step 3: Use the ideal gas law again to find the final volume. Rearrange the equation to solve for V: V = (nRT) / P. Plug in the values: V = (1 mol * 1.35 atm * 253 K) / 3.400 atm = 100 L.

So, the volume of gas in the balloon at 1.35 atm and 253 K is 100 L.

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