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The following molecule contains two functional groups, an alkane group and an alkyne.

CH₃-CHBr-CH=CH₂
a. True
b. False

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Final answer:

The molecule CH₃-CHBr-CH=CH₂ contains both an alkane group and an alkyne group.

Step-by-step explanation:

The molecule CH₃-CHBr-CH=CH₂ contains both an alkane group and an alkyne group. An alkane is a hydrocarbon with only carbon-carbon single bonds, while an alkyne is a hydrocarbon with one or more carbon-carbon triple bonds. In this molecule, the CH₃-CHBr part represents an alkane, and the CH=CH₂ part represents an alkyne. Therefore, the statement is True.

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