Final answer:
The molecule CH₃-CHBr-CH=CH₂ contains both an alkane group and an alkyne group.
Step-by-step explanation:
The molecule CH₃-CHBr-CH=CH₂ contains both an alkane group and an alkyne group. An alkane is a hydrocarbon with only carbon-carbon single bonds, while an alkyne is a hydrocarbon with one or more carbon-carbon triple bonds. In this molecule, the CH₃-CHBr part represents an alkane, and the CH=CH₂ part represents an alkyne. Therefore, the statement is True.