Question

Aluminum has a density of 2.70 g/ mL. What volume is occupied by a block of aluminum that weighs 4.32 kg?

A) 0.000625 mL
B) 0.625 mL
C) 1.60 mL
D) 1.60 L

Answer 1

The volume occupied by the block of aluminum that weighs 4.32 kg is 1.60 L.

Step-by-step explanation:

To find the volume of the block of aluminum, we can use the formula:

Density = Mass/Volume

Rearranging the formula to solve for volume, we have:

Volume = Mass/Density

Given that the mass of the block of aluminum is 4.32 kg and the density is 2.70 g/mL, we need to convert the mass to grams and then divide by the density to find the volume.

Converting 4.32 kg to grams:

1. 1 kg = 1000 g
2. 4.32 kg = 4.32 x 1000 g = 4320 g

Now, divide 4320 g by the density of 2.70 g/mL:

1. Volume = 4320 g / 2.70 g/mL = 1600 mL

Therefore, the volume occupied by the block of aluminum is 1600 mL or 1.60 L.