Question

Practice using Charles's law. A balloon with a volume of 2.0 L at 25°C is placed in a hot room at 35°C. The pressure on the balloon is constant at 1.0 atm. According to the formula V1 * T1 = V2 * T2, how does the volume of the balloon change after moving it to the hot room?

1) Increases
2) Decreases
3) Remains the same
4) Cannot be determined

Answer 1

Under the principle of Charles's law, the volume of the balloon increases when it is moved to a hotter environment, from 25°C to 35°C, while the pressure remains constant at 1.0 atm.

Step-by-step explanation:

According to Charles's law, the volume of a gas is directly proportional to its temperature on the Kelvin scale, provided the pressure is constant. In the scenario where a balloon with an initial volume of 2.0 L is at 25°C (which is 298.15 K when converted to Kelvin) and is placed in a hot room at 35°C (308.15 K), we can use the formula V1 * T1 = V2 * T2 to determine how the volume changes. Since the temperature increases when the balloon is moved to the hot room, the volume of the gas will also increase to maintain the equality.

Applying Charles's law, we have:
V1 * T1 = V2 * T2
which gives us:
2.0 L * 298.15 K = V2 * 308.15 K

Solving for V2, we find that the volume of the balloon increases. This demonstrates the direct relationship between temperature and volume for a gas at constant pressure.