Question

The player in the previous problem then kicks the ball with the same speed but at 60.0° from the horizontal. What is the ball's hang time, horizontal distance traveled, and maximum height?

Answer 1

The time of flight, horizontal distance, and maximum height of a projectile can be calculated using the velocity components and the acceleration due to gravity, following the principles of projectile motion in Physics.

Step-by-step explanation:

The question relates to the principles of projectile motion, which is part of classical mechanics in Physics. When the ball is kicked at a 60.0° angle from the horizontal, we can use the kinematic equations to calculate the hang time, horizontal distance, and maximum height. We can break the initial velocity into horizontal (vx) and vertical (vy) components using trigonometry, where vx = vinitial × cos(θ) and vy = vinitial × sin(θ). The hang time, or time of flight, T, can be found from the vertical motion, with T = 2 × vy / g, where g represents the acceleration due to gravity. The horizontal distance, R, is calculated using R = vx × T. Lastly, the maximum height, H, is given by H = (vy)2 / (2 × g).