Question

The following successive dilutions are applied to a stock solution that is 6.65 m sucrose: solution a = 57.0 ml of the stock solution is diluted to 105 ml solution b = 46.0 ml of solution a is diluted to 350. ml solution c = 105 ml of solution b is diluted to 225 ml. What is the concentration of sucrose in solution c?

Answer 1

The concentration of sucrose in solution C is found by applying the dilution formula M1V1 = M2V2 successively for each dilution step, starting from solution A through solution C.

Step-by-step explanation:

To calculate the concentration of sucrose in solution C, we must apply the concept of dilution. Dilution is the process of reducing the concentration of a solute in a solution by mixing it with more solvent. We will use the dilution formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, respectively, and M2 and V2 are the molarity and volume of the final solution, respectively.

• Solution A starts with a 6.65 M stock solution. When 57.0 mL is diluted to 105 mL, we have:

M1V1 = M2V2
6.65 M * 57.0 mL = M2 * 105 mL
M2 (Concentration of Solution A) = (6.65 * 57.0) / 105

• Solution B is made by diluting Solution A. 46.0 mL of Solution A is diluted to 350 mL, we calculate:

M1V1 = M2V2
(M2 from Solution A) * 46.0 mL = M3 * 350 mL
M3 (Concentration of Solution B) = (M2 * 46.0) / 350

• Solution C is made by diluting Solution B. 105 mL of Solution B is diluted to 225 mL. Using the concentration found for Solution B, we calculate:

M1V1 = M2V2
(M3 from Solution B) * 105 mL = M4 * 225 mL
M4 (Concentration of Solution C) = (M3 * 105) / 225

After calculating each step, the concentration of sucrose in Solution C will be the final value of M4.