Question

The heaviest edible mushroom ever found (the so-called 'chicken of the woods') had a mass of 45.4 kg. Suppose such a mushroom is attached to a rope and pulled horizontally along a smooth stretch of ground, so that it undergoes a constant acceleration of 0.35 m/s². If the mushroom is initially at rest, what will its velocity be after it has been displaced 64 m?

Answer 1

To calculate the final velocity of the mushroom after being displaced 64 m with a constant acceleration of 0.35 m/s², we use the kinematic equation v² = u² + 2as and find that the final velocity is approximately 6.69 m/s.

Step-by-step explanation:

The student asked about the final velocity of the heaviest edible mushroom, assumed to be 'chicken of the woods' with a mass of 45.4 kg being pulled along a smooth stretch of ground. The mushroom undergoes a constant acceleration of 0.35 m/s² after being pulled from rest and displaced by 64 m. To find the final velocity, we can use the kinematic equation:

v² = u² + 2as

Where:

• v is the final velocity
• u is the initial velocity (0 m/s since it starts from rest)
• a is the acceleration (0.35 m/s²)
• s is the displacement (64 m)

Plugging in the values we get:

v² = 0 + 2 * 0.35 * 64

v² = 44.8

v = √44.8

v = 6.69 m/s (to two decimal places)

Therefore, the final velocity of the mushroom after being displaced 64 m is approximately 6.69 m/s.