Question

The electron in a doubly-ionized lithium atom (Li₂) undergoes a transition from the n1 = 3 state to the n2 = 1 state. What is the change in energy of the electron during this transition?

Answer 1

The change in energy of the electron during the transition from the n1=3 state to the n2=1 state in a doubly-ionized lithium atom (Li²) can be calculated using the Bohr model.

Step-by-step explanation:

The change in energy of an electron during a transition from the n1 = 3 state to the n2 = 1 state in a doubly-ionized lithium atom (Li²) can be calculated using the Bohr model. In the Bohr model, the energy of an electron in a given energy level is given by the equation:

E = -13.6 × Z² / n²

Where E is the energy, Z is the atomic number of the nucleus, and n is the principal quantum number of the energy level. The change in energy (ΔE) can be calculated by subtracting the energy of the initial state (n1 = 3) from the energy of the final state (n2 = 1):

ΔE = -13.6 × Z² * (1/n2² - 1/n1²)

Substituting the values Z = 2 and n1 = 3, n2 = 1 for a doubly-ionized lithium atom, the change in energy can be calculated.