Question

For the following reaction:

H3PO4 + 3 KOH K3PO4 + 3 H2O

Calculate the normality of a solution that contains 3.61 grams of H3PO4 in 766 mL of solution.

Answer 1

To calculate the normality of a solution, divide the number of moles of solute by the volume of the solution in liters. In this case, the normality of the solution containing 3.61 grams of H3PO4 in 766 mL of solution is 0.048 M.

Step-by-step explanation:

To calculate the normality of a solution, we need to first calculate the number of moles of H3PO4 present in the solution and then divide it by the volume of the solution in liters.

Given that the solution contains 3.61 grams of H3PO4, we can calculate the number of moles using the formula:

moles = mass / molar mass

The molar mass of H3PO4 is 98 g/mol. Therefore, the number of moles of H3PO4 is:

moles = 3.61 g / 98 g/mol = 0.0368 mol

The volume of the solution is given as 766 mL, which is equivalent to 0.766 L. Therefore, the normality of the solution is:

normality = moles / volume = 0.0368 mol / 0.766 L = 0.048 M