Final answer:
If cyclist 1 is moving at a velocity of 5 m/s east and cyclist 2 at 3 m/s west from the Earth's reference frame, then the velocity of cyclist 1 from cyclist 2's frame of reference is 8 m/s east due to the principle of relative velocities.
Step-by-step explanation:
To determine the velocity of cyclist 1 from the frame of reference of cyclist 2, we must understand relative motion and reference frames. Without additional information about the velocities of both cyclists, we cannot give a specific answer. Let's assume cyclist 1 is moving east and cyclist 2 is moving west. If cyclist 1 is moving with a velocity of 5 m/s east relative to Earth, and cyclist 2 is also moving with a velocity of 3 m/s west relative to Earth, then we need to determine what cyclist 1's velocity is from cyclist 2's perspective. Using the principle of relative velocities, we subtract the velocity of cyclist 2 from cyclist 1, as they are moving in opposite directions.
So, cyclist 1's velocity from the perspective of cyclist 2 would be:
Velocity of Cyclist 1 - Velocity of Cyclist 2 = 5 m/s east - (-3 m/s west) = 5 m/s + 3 m/s = 8 m/s east
Thus the velocity of cyclist 1 from cyclist 2's frame of reference is 8 m/s east.