Question

The concentrations at equilibrium are [N₂] = 0.44 M and [O₂] = 0.62 M, and k = 2.1 × 10–3. Find [NO] at equilibrium.

Answer 1

To find the equilibrium concentration of NO, the equilibrium constant expression is used: k = [NO]²/([N₂][O₂]). Given k = 2.1 × 10⁻³, [N₂] = 0.44 M, and [O₂] = 0.62 M, the equilibrium concentration of NO is calculated to be 0.0239 M.

Step-by-step explanation:

To calculate the equilibrium concentration of NO, we use the provided equilibrium constant (k) and the given concentrations of N₂ and O₂. The reaction under consideration is N₂(g) + O₂(g) ⇒ 2NO(g), and its equilibrium constant (k) expression is k = [NO]²/([N₂][O₂]). Given that k = 2.1 × 10⁻³, [N₂] = 0.44 M, and [O₂] = 0.62 M, we solve for [NO] as follows:

[NO]² = k[N₂][O₂]

[NO]² = (2.1 × 10⁻³)(0.44 M)(0.62 M)

[NO]² = 0.0005724 M²

[NO] = √(0.0005724 M²)

[NO] = 0.0239 M (rounded to four significant figures)

The equilibrium concentration of NO at equilibrium is 0.0239 M.