9.4k views
3 votes
The bond dissociation energy to break 3 N-H bond(s) in 1 mole of NH₃ molecules is ________?

User Yastanub
by
7.3k points

1 Answer

2 votes

Final answer:

The bond dissociation energy to break 3 N-H bonds in 1 mole of NH3 molecules is 579 kJ/mol.

Step-by-step explanation:

The bond dissociation energy to break 3 N-H bonds in 1 mole of NH3 molecules can be calculated by using the bond dissociation energy of the N-H bond. According to the given information, the bond dissociation energy for the N-H bond is approximately 193 kJ/mol. Since each NH3 molecule has 3 N-H bonds, the bond dissociation energy for 3 N-H bonds in 1 mole of NH3 molecules would be:



Bond dissociation energy = 3 N-H bonds × (193 kJ/mol)



= 579 kJ/mol

User Geparada
by
7.4k points