Final answer:
The bond dissociation energy for 3 N-H bonds in NH3 would be thrice the bond dissociation energy for a single N-H bond. A numeric value cannot be provided without knowing the specific bond energy for N-H from a reference source.
Step-by-step explanation:
The bond dissociation energy for the N-H bonds in NH3 must be determined to answer the given question. Unfortunately, the information provided does not give a direct numerical value for this. However, it is known that each type of chemical bond has a characteristic bond dissociation energy, which represents the energy needed to break one mole of the bond.
For example, a general C-H bond requires about 100 kcal/mol (which is approximately 418.4 kJ/mol) to break. Even though these values vary slightly from molecule to molecule, they provide a basis for estimation. To find the bond dissociation energy for 3 N-H bonds in NH3, one would look up the standard bond energy of an N-H bond in a table of bond dissociation energies and then multiply that number by 3 for the three N-H bonds in NH3.
To break one mole of H-H bonds, it takes 436 kJ, and this is an example of a specific bond dissociation energy. Similarly, the dissociation energy for the N-H bond, if known, could be used in the same way.