Final answer:
To calculate the mass of lithium hydroxide produced, one must know the balanced chemical equation and the quantities of the other reactants. Using stoichiometry, molar mass, and the mole ratio from the equation, one can find the mass of lithium hydroxide involved in the reaction.
Step-by-step explanation:
To determine the mass of lithium hydroxide produced in a reaction, one would first need a balanced chemical equation of the corresponding reaction and the initial conditions or quantities of the reactants involved. For instance, in an aqueous solution where hydrochloric acid reacts with lithium hydroxide to form lithium chloride and water, the balanced equation is HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l). If you know the molarity and volume of lithium hydroxide solution and the stoichiometry of the reaction, you can use molar mass and stoichiometry to calculate the mass of lithium hydroxide produced or required.
Moreover, in the example of relating masses of reactants and products, if we were asked about magnesium hydroxide production, the balanced chemical equation is MgCl2(aq) + 2NaOH(aq) → Mg(OH)2(s) + 2NaCl(aq). To find out the mass of sodium hydroxide needed to produce 16 g of magnesium hydroxide, you'd use stoichiometry: Calculate the molar mass of magnesium hydroxide, determine the number of moles in 16 g, then use the mole ratio from the balanced equation to find the number of moles of sodium hydroxide needed, and finally convert that number to grams using the molar mass of sodium hydroxide.