66.6k views
4 votes
What mass of solute is required to produce 416.6 ml of a 0.152 m solution of kbr?

User Monadoboi
by
8.1k points

1 Answer

2 votes

Final answer:

To determine the mass of KBr solute required to make 416.6 ml of a 0.152 m solution, convert the volume to liters, use the molarity to find moles, and then convert moles to grams using the molar mass of KBr.

Step-by-step explanation:

The question 'What mass of solute is required to produce 416.6 ml of a 0.152 m solution of KBr?' requires the application of molarity concepts in chemistry. To find the mass of the solute KBr needed, we use the formula:

Mass of solute (g) = Molarity (M) × Volume of solution (L) × Molar mass of solute (g/mol)

First, convert the volume from mL to L:

416.6 mL = 0.4166 L

Then, identify the molarity as 0.152 M and the molar mass of KBr (potassium bromide) as 119 g/mol. With these values, we calculate the moles of KBr:

Moles of KBr = 0.152 M × 0.4166 L

Finally, we convert moles to mass using the molar mass of KBr:

Mass of KBr = Moles of KBr × Molar mass of KBr

Through this process, we can determine the mass of solute required for the solution.

User DennisLi
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.