Final answer:
The ratio of the magnitude of the radial acceleration of ladybug 2 to ladybug 1 is 2.08.
Step-by-step explanation:
The ratio of the magnitude of the radial acceleration of ladybug 2 to ladybug 1 can be determined based on the circular motion they are experiencing. The radial acceleration of an object moving in a circle can be calculated using the formula a = v^2 / r, where a is the radial acceleration, v is the tangential velocity, and r is the radius of the circle.
If ladybug 2 has a tangential velocity of 5 m/s and a radius of 2 meters, the radial acceleration can be calculated as a = (5^2) / 2 = 12.5 m/s^2. If ladybug 1 has a tangential velocity of 3 m/s and a radius of 1.5 meters, the radial acceleration can be calculated as a = (3^2) / 1.5 = 6 m/s^2. Therefore, the ratio of the magnitude of the radial acceleration of ladybug 2 to that of ladybug 1 is 12.5/6 = 2.08.