Question

What is the frequency of yellow

light with E= 3.4 x 10-19 J?
h=6.626 x 10-34 J. S
x 10²¹ Hz
[?] x 10⁰

Answer 1

5.131 × 10¹⁴ Hz

Explanation:

Planck relation

`\large\boxed{E = hf}`

where:

• E = Energy of the photon (J).
• h = Planck's constant (J · s).
• f = frequency of light produced (Hz).

Given values:

• E = 3.4 × 10⁻¹⁹ J
• h = 6.626 × 10⁻³⁴ J · s

Substitute the given values into the formula and solve for f:

`\implies 3.4 * 10^(-19)=(6.626 * 10^(-34))f`

`\implies f=(3.4 * 10^(-19))/(6.626 * 10^(-34))`

`\implies f=(3.4)/(6.626) * (10^(-19))/(10^(-34))`

`\implies f=0.5131* 10^((-19-(-34)))`

`\implies f=0.5131 * 10^(15)`

`\implies f=5.131 * 10^(14)`