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What is the equation of a line perpendicular to y-4=5/2(x-2) that passes through (-1,-4)?

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Final answer:

The equation of the line perpendicular to the line y - 4 = 5/2(x - 2) that passes through the point (-1, -4) is y = -2/5x - 14/5.

Step-by-step explanation:

The equation of a line that is perpendicular to another line can be found by taking the negative reciprocal of the original line's slope.

In this case, the line y - 4 = 5/2(x - 2) has a slope of 5/2.

The slope of the perpendicular line would then be the negative reciprocal, which is -2/5.

Next, we use the point-slope form of a line's equation, which is (y - y1) = m(x - x1), where m is the slope and (x1, y1) is the given point through which the line passes.

Plugging in the slope -2/5 and the point (-1, -4) into this form gives us the perpendicular line's equation:

y + 4 = -2/5(x + 1)

Finally, to convert this into slope-intercept form (y = mx + b), we simplify the equation to get:

y = -2/5x - 14/5

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