Question

The range is the horizontal distance from the cannon when the pumpkin hits the ground. This distance is given by the product of the horizontal velocity (which is constant) and the amount of time the pumpkin is in the air (which is determined by the vertical component of the initial velocity, as you just discovered). Set the initial speed to 14 m/s, and fire the pumpkin several times while varying the angle between the cannon and the horizontal.

Required:
For which angle is the range a maximum (with the initial speed held constant)?

Answer 1

Step-by-step explanation:

For range o a projectile , the formula is as follows

R = u² sin2Ф / g where u is initial velocity of throw , Ф is angle of throw and g is acceleration due to gravity .

Here u = 14 m /s

R = 14² sin2Ф / 9.8

R = 20 sin2Ф

Now R will have maximum value when sin2Ф has maximum value .

Maximum value of sin2Ф = 1

sin2Ф = 1 = sin 90°

Ф = 45°

So when throw is aimed at 45° , range will be maximum .