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What is the copper(ii)-ion concentration at 25°C in the cell following cell if the measured cell potential is 1.03 V?

User JadedCore
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Final answer:

The concentration of copper(II)-ion at 25°C in the cell can be determined using the Nernst equation.

Step-by-step explanation:

The concentration of the Copper(II)-ion at 25°C in the cell can be determined using the Nernst equation. The Nernst equation is given by: Ecell = E°cell - (0.0592/n) * log([Cu²+]/[Cu²+]°). Given that the measured cell potential is 1.03 V, we can use this equation to solve for [Cu²+]. We also need to take into account the temperature coefficient, which is 0.0592/n, where n is the number of electrons involved in the half-reaction.

By rearranging the Nernst equation, we have: [Cu²+] = [Cu²+]° * 10^((E°cell - Ecell) * n/0.0592). Plugging in the values, [Cu²+] = 1.0 * 10^-7 * 10^((0.34 - 1.03) * 2/0.0592) = 8.96 * 10^-8 M.

User Meera Datey
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