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20 votes
Please can someone just answer question 7C

Please can someone just answer question 7C-example-1
User Rajeev Akotkar
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2.5k points

2 Answers

21 votes
21 votes

Answer:

y=-2/3*x-1

Explanation:

3x-2y+5=0

Solving for y

-2y=-3x-5

y=3/2*x+5/2

-2/3 is perpendicular to 3/2, so the slope must be -2/3

y=-2/3*x+b

Substituting x=0 and y=-1,

-1=b

Therefore, the equation of the line is y=-2/3*x-1

User Mdaoust
by
2.7k points
13 votes
13 votes

Answer:

y = -2/3x - 1

Explanation:

Step 1: The first thing that we need to do is to find the slope of a given line

The explicit equation of a given line is: y = 3/2x + 5/2

So the slope is m = 3/2:

Step 2: The perpendicular slope (m1) is negative reciprocal of the slope m.

m1 = -2/3

So the perpendicular line will have a slope of m1 = -2/3

Step 3: Now we have a point and the slope so we can use point-slope form, which is: y - y0 = m1(x - x0)

In this example we have: m1 = -2/3, x0 = 0 and y0 = -1. After substitution we have:

y - y0 = m1(x - x0)

y - (-1) = -2/3(x - 0)

y + 1 = -2/3x + 0

y = -2/3x + 0 - 1

y = -2/3x - 1

Please can someone just answer question 7C-example-1
User Josh Hemann
by
2.6k points