Question

A person got a score of 4.78 on a test, which turned out to be a Z score of +1.5. What percentage of cases are above this score? (Assume a normal distribution.)

1. 100% - 43.32% = 56.68%

2. 43.32% - 50% = -6.68%

3. 50% + 43.32% = 83.32%

4. 50% - 43.32% = 6.68%

Answer 1

To find the percentage of cases above a given score, use the z-table to find the area to the left of the z-score and subtract it from 1. In this case, the percentage is 6.68%.

Step-by-step explanation:

To find the percentage of cases that are above a given score using the standard normal distribution, we need to find the area under the curve to the left of the z-score. In this case, the z-score is +1.5.

Using a z-table, we can determine that the area to the left of +1.5 is approximately 0.9332.

To find the area above the z-score, we subtract this value from 1, giving us 1 - 0.9332 = 0.0668, or 6.68%.